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Design current Ib: single-phase and three-phaseWhat's Ib on a three-phase circuit?

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Design current Ib: single-phase

What it's for: finding how many amps a circuit will draw. That's the design current, Ib (capital I, small b). It's the first number in every design, and it depends only on the load.

Ib = P ÷ V
P = total wattage of the load (W) · V = voltage present at the origin of the circuit (V) · Ib in amps (A). It's the power triangle with I covered.

Be careful not to say "always use 230 V". It's normally U0, the voltage to earth, 230 V. But really it's the voltage present at the point where the circuit starts.

DB1 230 V distribution circuit loses 5 V (voltage drop) DB2 225 V final circuits Final circuits from DB2: work out Ib with 225 V, not 230 V
Our sketch. A distribution circuit from DB1 to DB2 drops 5 V, so only 225 V is present at DB2. For final circuits leaving DB2, use 225 V. Work with the voltage that's actually there.

Another example: the same load at DB1 and at DB2

3 kW heater on a final circuit
From DB1 (230 V):  Ib = 3000 ÷ 230 = 13.04 A
From DB2 (225 V):  Ib = 3000 ÷ 225 = 13.33 A
Less voltage → a little more current for the same power.

8 A).

Level 3 vs Level 4
You may also see √3 and a power factor brought into current calculations. Power factor is Level 4 design work, so it's left out here. At Level 3, when you want the amps in a circuit, use the power triangle: I = P ÷ V. (If you know the volts and the resistance instead, that's Ohm's law, I = V ÷ R.)

Design current Ib: three-phase

What it's for: the design current of a three-phase circuit, where the load is spread across the three phases. The answer is the current per phase.

Ib = P ÷ (√3 × VL)
P = total power (W) · VL = voltage between lines, normally 400 V · √3 = 1.73 · Ib in amps per phase

Unlike single-phase, you don't use the 230 V to earth (less any volt drop). Three-phase Ib is based on the 400 V between lines. If you don't like the √ key on your calculator, just type 1.73.

Worked example: 5 kW three-phase circuit

Ib = P ÷ (√3 × VL)
   = 5000 ÷ (1.732 × 400)
   = 5000 ÷ 692.8
   = 7.22 A per phase     (some sources give 7.21 A, just rounding)

L1, L2 and L3 each carry about 7.2 A
→ a 10 A circuit breaker would do.

You'll also hear it as "5000 over 400, divided by √3". That's the same sum: 5000 ÷ 400 = 12.5, then 12.5 ÷ 1.732 = 7.22 A.

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